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[Basic Level] Function implementations
Posted Feb 1, 2012, 12:26 p.m. EST Parameters, Variables, & Functions Version 4.2a 1 Reply
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Hello,
I defined a function "fun" in the "Global Definitions"
"fun" is a piece-wise function with the argument of time t. So fun(t), and this function works correctly.
I used physics "Transport of Diluted species", and I have a "Flux condition".
I choose "Inward Flux" with "Species c", and type the function for the flux condition.
But when i type "fun" or "fun(t)", it displays red.
So what is the formula of the function type : f[t] or f(t) or f{t} ?
I defined a function "fun" in the "Global Definitions"
"fun" is a piece-wise function with the argument of time t. So fun(t), and this function works correctly.
I used physics "Transport of Diluted species", and I have a "Flux condition".
I choose "Inward Flux" with "Species c", and type the function for the flux condition.
But when i type "fun" or "fun(t)", it displays red.
So what is the formula of the function type : f[t] or f(t) or f{t} ?
1 Reply Last Post Feb 1, 2012, 12:56 p.m. EST
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Posted:
1 decade ago
Hi
normally it's fun(any_name), your argument "t" used for the deifnition is a dummy name, you can chose x or w or ...
What might happen is that you need the full path to access it, depends on the branches and travel across the model tree. Then it's either something like root.fun() or root.mod1.fun() or something in between depoends on how you set up the model tree
Check alos the doc User manual p126 (42a) about variable naming and p 149 about global and local funcions
--
Good luck
Ivar
normally it's fun(any_name), your argument "t" used for the deifnition is a dummy name, you can chose x or w or ...
What might happen is that you need the full path to access it, depends on the branches and travel across the model tree. Then it's either something like root.fun() or root.mod1.fun() or something in between depoends on how you set up the model tree
Check alos the doc User manual p126 (42a) about variable naming and p 149 about global and local funcions
--
Good luck
Ivar