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Rotating Cylinder
Posted Oct 19, 2009, 9:13 a.m. EDT 3 Replies
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Hi,
In the Heat Transfer Module (General heat transfer, Transient Analysis (2D)) I want to rotate a 2D cylinder in time(to simulate the heating and cooling of a cylinder in time). Does anyone know if I can do this rotational transformation? ( X: r * sin (omega * t) Y: r * cos (omega *t) ) and where I have to implement this?
Thank you on advance,
P
In the Heat Transfer Module (General heat transfer, Transient Analysis (2D)) I want to rotate a 2D cylinder in time(to simulate the heating and cooling of a cylinder in time). Does anyone know if I can do this rotational transformation? ( X: r * sin (omega * t) Y: r * cos (omega *t) ) and where I have to implement this?
Thank you on advance,
P
3 Replies Last Post Oct 20, 2009, 3:47 a.m. EDT
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Posted:
1 decade ago
Hi
what about rotatating the source rather than the cylinder, apart from the minus sign in the velocity it should be the same. If I understand you, you have a 2D model x,y plane seen along the axis in Z, if your source is applied to the boundary you can delimit it with a bolean function for a certain angular width, given an angular rotational velocity times the time "t".
Check the laser soldering example in the doc, or is it in the models ?
Good luck
Ivar
what about rotatating the source rather than the cylinder, apart from the minus sign in the velocity it should be the same. If I understand you, you have a 2D model x,y plane seen along the axis in Z, if your source is applied to the boundary you can delimit it with a bolean function for a certain angular width, given an angular rotational velocity times the time "t".
Check the laser soldering example in the doc, or is it in the models ?
Good luck
Ivar
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Posted:
1 decade ago
Hi Ivar,
Thank you a lot for your answer, I will try if it works and keep you up to date.
P
Thank you a lot for your answer, I will try if it works and keep you up to date.
P
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Posted:
1 decade ago
Hi Ivar,
Thank you a lot for your answer, I will try if it works and keep you up to date.
P
Thank you a lot for your answer, I will try if it works and keep you up to date.
P